2016 Mathematics HSC 2 Unit
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1)
a
B
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2)
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C
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3)
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B
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4)
a
A
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s
An odd function look the same when rotated $180^\circ$ around the origin. Therefore A
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5)
a
B
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6)
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A
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7)
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A
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8)
a
D
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9)
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C
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10)
a
D
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11a)
a
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11b)
a
$-\frac{10}{(3x-4)^2}$
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11c)
a
$-1\le x\le5$
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11d)
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$10$
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11e)
a
Points of intersection are $(4,-21)$ and $(-2,3)$
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11f)
a
Gradient of tangent is $1.17$
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11g)
a
$x=\frac{\pi}{3},\frac{5\pi}{3}$
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12ai)
a
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12aii)
a
$AD=\frac{19}{5}$
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12aiii)
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Area$=\frac{19}{2}$ square units
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12bi)
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12bii)
a
$x=29$
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12c)
a
$\theta=69^\circ$ to the nearest degree
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12di)
a
$\frac{dy}{dx}=e^{3x}(1+3x)$
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12dii)
a
$6e^6$
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13ai)
a
Local maximum at $x=3$, ie at $(3,27)$
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13aii)
a
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13bi)
a
Focal Length$=3$
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13bii)
a
Focus $(2,2)$
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13ci)
a
A$=10$
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13cii)
a
$k=\frac{\ln\left(\frac12\right)}{-163}$
$\approx0.004252436$
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13d)
a
$\frac{4}{\pi}-\frac12$ square units
or $\frac{8-\pi}{2\pi}$ square units
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14a)
a
Area$\approx1.4$m$^2$
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14bi)
a
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14bii)
a
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14biii)
a
$A_{14}\approx14500$
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14ci)
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14cii)
a
Minimum length$=120$
at $x=12$, $\frac{d^2l}{dx^2}=\frac{1440}{12^3}>0$ therefore a minimum.
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14d)
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$5$
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14e)
a
$45\log2$
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15a)
a
$V=\frac{40\pi}{3}$
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15bi)
a
Explain question.
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15bii)
a
$n=12$
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15ci)
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15cii)
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15ciii)
a
$h=\frac{y}{x}$
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16ai)
a
$v=-2$
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16aii)
a
$a=1$ms$^{-2}$
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16aiii)
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16aiv)
a
Distance travelled$=10+8\log2-4\log2^3$
or distance travelled$=10+8\log2-12\log2$
or distance travelled$=10-4\log2$
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16bi)
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16bii)
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$10\le y<200$
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16biii)
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16biv)
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Population growing fastest when population is $y=100$
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Answers
1) B
2) C
3) B
4) A
5) B
6) A
7) A
8) D
9) C
10) D
11a)
11b) $-\frac{10}{(3x-4)^2}$
11c) $-1\le x\le5$
11d) $10$
11e) Points of intersection are $(4,-21)$ and $(-2,3)$
11f) Gradient of tangent is $1.17$
11g) $x=\frac{\pi}{3},\frac{5\pi}{3}$
12ai) Show that question.
Look at solution.
12aii) $AD=\frac{19}{5}$
12aiii) Area$=\frac{19}{2}$ square units
12bi) Show that question.
Look at solution.
12bii) $x=29$
12c) $\theta=69^\circ$ to the nearest degree
12di) $\frac{dy}{dx}=e^{3x}(1+3x)$
12dii) $6e^6$
13ai) Local maximum at $x=3$, ie at $(3,27)$
13aii)
13bi) Focal Length$=3$
13bii) Focus $(2,2)$
13ci) A$=10$
13cii) $k=\frac{\ln\left(\frac12\right)}{-163}$
$\approx0.004252436$
13d) $\frac{4}{\pi}-\frac12$ square units
or $\frac{8-\pi}{2\pi}$ square units
14a) Area$\approx1.4$m$^2$
14bi) Show that question.
Look at solution.
14bii) Show that question.
Look at solution.
14biii) $A_{14}\approx14500$
14ci) Show that question.
Look at solution.
14cii) Minimum length$=120$
at $x=12$, $\frac{d^2l}{dx^2}=\frac{1440}{12^3}>0$ therefore a minimum.
14d) $5$
14e) $45\log2$
15a) $V=\frac{40\pi}{3}$
15bi) Explain question.
Look at solution.
15bii) $n=12$
15ci) Show that question.
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15cii) Show that question.
Look at solution.
15ciii) $h=\frac{y}{x}$
16ai) $v=-2$
16aii) $a=1$ms$^{-2}$
16aiii)
16aiv) Distance travelled$=10+8\log2-4\log2^3$
or distance travelled$=10+8\log2-12\log2$
or distance travelled$=10-4\log2$
16bi) Show that question.
Look at solution.
16bii) $10\le y<200$
16biii) Show that question.
Look at solution.
16biv) Population growing fastest when population is $y=100$
Solutions
1)
2)
3)
4) An odd function look the same when rotated $180^\circ$ around the origin. Therefore A
5)
6)
7)
8)
9)
10)
11a)
11b)
11c)
11d)
11e)
11f)
11g)
12ai)
12aii)
12aiii)
12bi)
12bii)
12c)
12di)
12dii)
13ai)
13aii)
13bi)
13bii)
13ci)
13cii)
13d)
14a)
14bi)
14bii)
14biii)
14ci)
14cii)
14d)
14e)
15a)
15bi)
15bii)
15ci)
15cii)
15ciii)
16ai)
16aii)
16aiii)
16aiv)
16bi)
16bii)
16biii)
16biv)